3.27.24 \(\int \frac {(5-x) (3+2 x)^{3/2}}{(2+5 x+3 x^2)^{5/2}} \, dx\) [2624]

3.27.24.1 Optimal result
3.27.24.2 Mathematica [A] (verified)
3.27.24.3 Rubi [A] (verified)
3.27.24.4 Maple [A] (verified)
3.27.24.5 Fricas [C] (verification not implemented)
3.27.24.6 Sympy [F]
3.27.24.7 Maxima [F]
3.27.24.8 Giac [F]
3.27.24.9 Mupad [F(-1)]

3.27.24.1 Optimal result

Integrand size = 29, antiderivative size = 175 \[ \int \frac {(5-x) (3+2 x)^{3/2}}{\left (2+5 x+3 x^2\right )^{5/2}} \, dx=-\frac {2 \sqrt {3+2 x} (121+139 x)}{9 \left (2+5 x+3 x^2\right )^{3/2}}+\frac {4 \sqrt {3+2 x} (1390+1689 x)}{9 \sqrt {2+5 x+3 x^2}}-\frac {2252 \sqrt {-2-5 x-3 x^2} E\left (\arcsin \left (\sqrt {3} \sqrt {1+x}\right )|-\frac {2}{3}\right )}{3 \sqrt {3} \sqrt {2+5 x+3 x^2}}+\frac {2956 \sqrt {-2-5 x-3 x^2} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {3} \sqrt {1+x}\right ),-\frac {2}{3}\right )}{3 \sqrt {3} \sqrt {2+5 x+3 x^2}} \]

output
-2/9*(121+139*x)*(3+2*x)^(1/2)/(3*x^2+5*x+2)^(3/2)+4/9*(1390+1689*x)*(3+2* 
x)^(1/2)/(3*x^2+5*x+2)^(1/2)-2252/9*EllipticE(3^(1/2)*(1+x)^(1/2),1/3*I*6^ 
(1/2))*(-3*x^2-5*x-2)^(1/2)*3^(1/2)/(3*x^2+5*x+2)^(1/2)+2956/9*EllipticF(3 
^(1/2)*(1+x)^(1/2),1/3*I*6^(1/2))*(-3*x^2-5*x-2)^(1/2)*3^(1/2)/(3*x^2+5*x+ 
2)^(1/2)
 
3.27.24.2 Mathematica [A] (verified)

Time = 31.31 (sec) , antiderivative size = 196, normalized size of antiderivative = 1.12 \[ \int \frac {(5-x) (3+2 x)^{3/2}}{\left (2+5 x+3 x^2\right )^{5/2}} \, dx=-\frac {\frac {22520 \left (2+5 x+3 x^2\right )}{\sqrt {3+2 x}}-\frac {30 \sqrt {3+2 x} \left (1813+6839 x+8410 x^2+3378 x^3\right )}{2+5 x+3 x^2}+\frac {11260 (1+x) \sqrt {\frac {2+3 x}{3+2 x}} E\left (\arcsin \left (\frac {\sqrt {\frac {5}{3}}}{\sqrt {3+2 x}}\right )|\frac {3}{5}\right )}{\sqrt {\frac {1+x}{15+10 x}}}-\frac {2392 (1+x) \sqrt {\frac {2+3 x}{3+2 x}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {\frac {5}{3}}}{\sqrt {3+2 x}}\right ),\frac {3}{5}\right )}{\sqrt {\frac {1+x}{15+10 x}}}}{45 \sqrt {2+5 x+3 x^2}} \]

input
Integrate[((5 - x)*(3 + 2*x)^(3/2))/(2 + 5*x + 3*x^2)^(5/2),x]
 
output
-1/45*((22520*(2 + 5*x + 3*x^2))/Sqrt[3 + 2*x] - (30*Sqrt[3 + 2*x]*(1813 + 
 6839*x + 8410*x^2 + 3378*x^3))/(2 + 5*x + 3*x^2) + (11260*(1 + x)*Sqrt[(2 
 + 3*x)/(3 + 2*x)]*EllipticE[ArcSin[Sqrt[5/3]/Sqrt[3 + 2*x]], 3/5])/Sqrt[( 
1 + x)/(15 + 10*x)] - (2392*(1 + x)*Sqrt[(2 + 3*x)/(3 + 2*x)]*EllipticF[Ar 
cSin[Sqrt[5/3]/Sqrt[3 + 2*x]], 3/5])/Sqrt[(1 + x)/(15 + 10*x)])/Sqrt[2 + 5 
*x + 3*x^2]
 
3.27.24.3 Rubi [A] (verified)

Time = 0.33 (sec) , antiderivative size = 177, normalized size of antiderivative = 1.01, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.310, Rules used = {1233, 25, 1235, 27, 1269, 1172, 27, 321, 327}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(5-x) (2 x+3)^{3/2}}{\left (3 x^2+5 x+2\right )^{5/2}} \, dx\)

\(\Big \downarrow \) 1233

\(\displaystyle \frac {2}{9} \int -\frac {423 x+722}{\sqrt {2 x+3} \left (3 x^2+5 x+2\right )^{3/2}}dx-\frac {2 \sqrt {2 x+3} (139 x+121)}{9 \left (3 x^2+5 x+2\right )^{3/2}}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {2}{9} \int \frac {423 x+722}{\sqrt {2 x+3} \left (3 x^2+5 x+2\right )^{3/2}}dx-\frac {2 \sqrt {2 x+3} (139 x+121)}{9 \left (3 x^2+5 x+2\right )^{3/2}}\)

\(\Big \downarrow \) 1235

\(\displaystyle -\frac {2}{9} \left (-\frac {2}{5} \int -\frac {15 (563 x+475)}{\sqrt {2 x+3} \sqrt {3 x^2+5 x+2}}dx-\frac {2 \sqrt {2 x+3} (1689 x+1390)}{\sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (139 x+121)}{9 \left (3 x^2+5 x+2\right )^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {2}{9} \left (6 \int \frac {563 x+475}{\sqrt {2 x+3} \sqrt {3 x^2+5 x+2}}dx-\frac {2 \sqrt {2 x+3} (1689 x+1390)}{\sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (139 x+121)}{9 \left (3 x^2+5 x+2\right )^{3/2}}\)

\(\Big \downarrow \) 1269

\(\displaystyle -\frac {2}{9} \left (6 \left (\frac {563}{2} \int \frac {\sqrt {2 x+3}}{\sqrt {3 x^2+5 x+2}}dx-\frac {739}{2} \int \frac {1}{\sqrt {2 x+3} \sqrt {3 x^2+5 x+2}}dx\right )-\frac {2 \sqrt {2 x+3} (1689 x+1390)}{\sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (139 x+121)}{9 \left (3 x^2+5 x+2\right )^{3/2}}\)

\(\Big \downarrow \) 1172

\(\displaystyle -\frac {2}{9} \left (6 \left (\frac {563 \sqrt {-3 x^2-5 x-2} \int \frac {\sqrt {6 (x+1)+3}}{\sqrt {3} \sqrt {1-3 (x+1)}}d\left (\sqrt {3} \sqrt {x+1}\right )}{\sqrt {3} \sqrt {3 x^2+5 x+2}}-\frac {739 \sqrt {-3 x^2-5 x-2} \int \frac {\sqrt {3}}{\sqrt {1-3 (x+1)} \sqrt {6 (x+1)+3}}d\left (\sqrt {3} \sqrt {x+1}\right )}{\sqrt {3} \sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (1689 x+1390)}{\sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (139 x+121)}{9 \left (3 x^2+5 x+2\right )^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {2}{9} \left (6 \left (\frac {563 \sqrt {-3 x^2-5 x-2} \int \frac {\sqrt {6 (x+1)+3}}{\sqrt {1-3 (x+1)}}d\left (\sqrt {3} \sqrt {x+1}\right )}{3 \sqrt {3 x^2+5 x+2}}-\frac {739 \sqrt {-3 x^2-5 x-2} \int \frac {1}{\sqrt {1-3 (x+1)} \sqrt {6 (x+1)+3}}d\left (\sqrt {3} \sqrt {x+1}\right )}{\sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (1689 x+1390)}{\sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (139 x+121)}{9 \left (3 x^2+5 x+2\right )^{3/2}}\)

\(\Big \downarrow \) 321

\(\displaystyle -\frac {2}{9} \left (6 \left (\frac {563 \sqrt {-3 x^2-5 x-2} \int \frac {\sqrt {6 (x+1)+3}}{\sqrt {1-3 (x+1)}}d\left (\sqrt {3} \sqrt {x+1}\right )}{3 \sqrt {3 x^2+5 x+2}}-\frac {739 \sqrt {-3 x^2-5 x-2} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {3} \sqrt {x+1}\right ),-\frac {2}{3}\right )}{\sqrt {3} \sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (1689 x+1390)}{\sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (139 x+121)}{9 \left (3 x^2+5 x+2\right )^{3/2}}\)

\(\Big \downarrow \) 327

\(\displaystyle -\frac {2}{9} \left (6 \left (\frac {563 \sqrt {-3 x^2-5 x-2} E\left (\arcsin \left (\sqrt {3} \sqrt {x+1}\right )|-\frac {2}{3}\right )}{\sqrt {3} \sqrt {3 x^2+5 x+2}}-\frac {739 \sqrt {-3 x^2-5 x-2} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {3} \sqrt {x+1}\right ),-\frac {2}{3}\right )}{\sqrt {3} \sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (1689 x+1390)}{\sqrt {3 x^2+5 x+2}}\right )-\frac {2 \sqrt {2 x+3} (139 x+121)}{9 \left (3 x^2+5 x+2\right )^{3/2}}\)

input
Int[((5 - x)*(3 + 2*x)^(3/2))/(2 + 5*x + 3*x^2)^(5/2),x]
 
output
(-2*Sqrt[3 + 2*x]*(121 + 139*x))/(9*(2 + 5*x + 3*x^2)^(3/2)) - (2*((-2*Sqr 
t[3 + 2*x]*(1390 + 1689*x))/Sqrt[2 + 5*x + 3*x^2] + 6*((563*Sqrt[-2 - 5*x 
- 3*x^2]*EllipticE[ArcSin[Sqrt[3]*Sqrt[1 + x]], -2/3])/(Sqrt[3]*Sqrt[2 + 5 
*x + 3*x^2]) - (739*Sqrt[-2 - 5*x - 3*x^2]*EllipticF[ArcSin[Sqrt[3]*Sqrt[1 
 + x]], -2/3])/(Sqrt[3]*Sqrt[2 + 5*x + 3*x^2]))))/9
 

3.27.24.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 321
Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> S 
imp[(1/(Sqrt[a]*Sqrt[c]*Rt[-d/c, 2]))*EllipticF[ArcSin[Rt[-d/c, 2]*x], b*(c 
/(a*d))], x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[a, 
0] &&  !(NegQ[b/a] && SimplerSqrtQ[-b/a, -d/c])
 

rule 327
Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[ 
(Sqrt[a]/(Sqrt[c]*Rt[-d/c, 2]))*EllipticE[ArcSin[Rt[-d/c, 2]*x], b*(c/(a*d) 
)], x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[a, 0]
 

rule 1172
Int[((d_.) + (e_.)*(x_))^(m_)/Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2], x_Sy 
mbol] :> Simp[2*Rt[b^2 - 4*a*c, 2]*(d + e*x)^m*(Sqrt[(-c)*((a + b*x + c*x^2 
)/(b^2 - 4*a*c))]/(c*Sqrt[a + b*x + c*x^2]*(2*c*((d + e*x)/(2*c*d - b*e - e 
*Rt[b^2 - 4*a*c, 2])))^m))   Subst[Int[(1 + 2*e*Rt[b^2 - 4*a*c, 2]*(x^2/(2* 
c*d - b*e - e*Rt[b^2 - 4*a*c, 2])))^m/Sqrt[1 - x^2], x], x, Sqrt[(b + Rt[b^ 
2 - 4*a*c, 2] + 2*c*x)/(2*Rt[b^2 - 4*a*c, 2])]], x] /; FreeQ[{a, b, c, d, e 
}, x] && EqQ[m^2, 1/4]
 

rule 1233
Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c 
_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(-(d + e*x)^(m - 1))*(a + b*x + c*x^2) 
^(p + 1)*((2*a*c*(e*f + d*g) - b*(c*d*f + a*e*g) - (2*c^2*d*f + b^2*e*g - c 
*(b*e*f + b*d*g + 2*a*e*g))*x)/(c*(p + 1)*(b^2 - 4*a*c))), x] - Simp[1/(c*( 
p + 1)*(b^2 - 4*a*c))   Int[(d + e*x)^(m - 2)*(a + b*x + c*x^2)^(p + 1)*Sim 
p[2*c^2*d^2*f*(2*p + 3) + b*e*g*(a*e*(m - 1) + b*d*(p + 2)) - c*(2*a*e*(e*f 
*(m - 1) + d*g*m) + b*d*(d*g*(2*p + 3) - e*f*(m - 2*p - 4))) + e*(b^2*e*g*( 
m + p + 1) + 2*c^2*d*f*(m + 2*p + 2) - c*(2*a*e*g*m + b*(e*f + d*g)*(m + 2* 
p + 2)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && LtQ[p, -1] && 
GtQ[m, 1] && ((EqQ[m, 2] && EqQ[p, -3] && RationalQ[a, b, c, d, e, f, g]) | 
|  !ILtQ[m + 2*p + 3, 0])
 

rule 1235
Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c 
_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(d + e*x)^(m + 1)*(f*(b*c*d - b^2*e + 2 
*a*c*e) - a*g*(2*c*d - b*e) + c*(f*(2*c*d - b*e) - g*(b*d - 2*a*e))*x)*((a 
+ b*x + c*x^2)^(p + 1)/((p + 1)*(b^2 - 4*a*c)*(c*d^2 - b*d*e + a*e^2))), x] 
 + Simp[1/((p + 1)*(b^2 - 4*a*c)*(c*d^2 - b*d*e + a*e^2))   Int[(d + e*x)^m 
*(a + b*x + c*x^2)^(p + 1)*Simp[f*(b*c*d*e*(2*p - m + 2) + b^2*e^2*(p + m + 
 2) - 2*c^2*d^2*(2*p + 3) - 2*a*c*e^2*(m + 2*p + 3)) - g*(a*e*(b*e - 2*c*d* 
m + b*e*m) - b*d*(3*c*d - b*e + 2*c*d*p - b*e*p)) + c*e*(g*(b*d - 2*a*e) - 
f*(2*c*d - b*e))*(m + 2*p + 4)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, 
 m}, x] && LtQ[p, -1] && (IntegerQ[m] || IntegerQ[p] || IntegersQ[2*m, 2*p] 
)
 

rule 1269
Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c 
_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[g/e   Int[(d + e*x)^(m + 1)*(a + b*x + 
 c*x^2)^p, x], x] + Simp[(e*f - d*g)/e   Int[(d + e*x)^m*(a + b*x + c*x^2)^ 
p, x], x] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x] &&  !IGtQ[m, 0]
 
3.27.24.4 Maple [A] (verified)

Time = 0.38 (sec) , antiderivative size = 231, normalized size of antiderivative = 1.32

method result size
elliptic \(\frac {\sqrt {\left (3+2 x \right ) \left (3 x^{2}+5 x +2\right )}\, \left (\frac {\left (-\frac {242}{81}-\frac {278 x}{81}\right ) \sqrt {6 x^{3}+19 x^{2}+19 x +6}}{\left (x^{2}+\frac {5}{3} x +\frac {2}{3}\right )^{2}}-\frac {2 \left (9+6 x \right ) \left (-\frac {2780}{27}-\frac {1126 x}{9}\right )}{\sqrt {\left (x^{2}+\frac {5}{3} x +\frac {2}{3}\right ) \left (9+6 x \right )}}+\frac {380 \sqrt {-20-30 x}\, \sqrt {3+3 x}\, \sqrt {45+30 x}\, F\left (\frac {\sqrt {-20-30 x}}{5}, \frac {\sqrt {10}}{2}\right )}{9 \sqrt {6 x^{3}+19 x^{2}+19 x +6}}+\frac {2252 \sqrt {-20-30 x}\, \sqrt {3+3 x}\, \sqrt {45+30 x}\, \left (\frac {E\left (\frac {\sqrt {-20-30 x}}{5}, \frac {\sqrt {10}}{2}\right )}{3}-F\left (\frac {\sqrt {-20-30 x}}{5}, \frac {\sqrt {10}}{2}\right )\right )}{45 \sqrt {6 x^{3}+19 x^{2}+19 x +6}}\right )}{\sqrt {3+2 x}\, \sqrt {3 x^{2}+5 x +2}}\) \(231\)
default \(-\frac {2 \left (1584 \sqrt {15}\, F\left (\frac {\sqrt {-20-30 x}}{5}, \frac {\sqrt {10}}{2}\right ) x^{2} \sqrt {-20-30 x}\, \sqrt {3+3 x}\, \sqrt {3+2 x}-3378 \sqrt {15}\, E\left (\frac {\sqrt {-20-30 x}}{5}, \frac {\sqrt {10}}{2}\right ) x^{2} \sqrt {-20-30 x}\, \sqrt {3+3 x}\, \sqrt {3+2 x}+2640 F\left (\frac {\sqrt {-20-30 x}}{5}, \frac {\sqrt {10}}{2}\right ) \sqrt {15}\, x \sqrt {-20-30 x}\, \sqrt {3+3 x}\, \sqrt {3+2 x}-5630 \sqrt {15}\, E\left (\frac {\sqrt {-20-30 x}}{5}, \frac {\sqrt {10}}{2}\right ) x \sqrt {-20-30 x}\, \sqrt {3+3 x}\, \sqrt {3+2 x}+1056 \sqrt {-20-30 x}\, \sqrt {3+3 x}\, \sqrt {15}\, \sqrt {3+2 x}\, F\left (\frac {\sqrt {-20-30 x}}{5}, \frac {\sqrt {10}}{2}\right )-2252 \sqrt {-20-30 x}\, \sqrt {3+3 x}\, \sqrt {15}\, \sqrt {3+2 x}\, E\left (\frac {\sqrt {-20-30 x}}{5}, \frac {\sqrt {10}}{2}\right )-304020 x^{4}-1212930 x^{3}-1750860 x^{2}-1086435 x -244755\right ) \sqrt {3 x^{2}+5 x +2}}{135 \left (1+x \right )^{2} \left (2+3 x \right )^{2} \sqrt {3+2 x}}\) \(308\)

input
int((5-x)*(3+2*x)^(3/2)/(3*x^2+5*x+2)^(5/2),x,method=_RETURNVERBOSE)
 
output
((3+2*x)*(3*x^2+5*x+2))^(1/2)/(3+2*x)^(1/2)/(3*x^2+5*x+2)^(1/2)*((-242/81- 
278/81*x)*(6*x^3+19*x^2+19*x+6)^(1/2)/(x^2+5/3*x+2/3)^2-2*(9+6*x)*(-2780/2 
7-1126/9*x)/((x^2+5/3*x+2/3)*(9+6*x))^(1/2)+380/9*(-20-30*x)^(1/2)*(3+3*x) 
^(1/2)*(45+30*x)^(1/2)/(6*x^3+19*x^2+19*x+6)^(1/2)*EllipticF(1/5*(-20-30*x 
)^(1/2),1/2*10^(1/2))+2252/45*(-20-30*x)^(1/2)*(3+3*x)^(1/2)*(45+30*x)^(1/ 
2)/(6*x^3+19*x^2+19*x+6)^(1/2)*(1/3*EllipticE(1/5*(-20-30*x)^(1/2),1/2*10^ 
(1/2))-EllipticF(1/5*(-20-30*x)^(1/2),1/2*10^(1/2))))
 
3.27.24.5 Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.09 (sec) , antiderivative size = 126, normalized size of antiderivative = 0.72 \[ \int \frac {(5-x) (3+2 x)^{3/2}}{\left (2+5 x+3 x^2\right )^{5/2}} \, dx=\frac {2 \, {\left (2147 \, \sqrt {6} {\left (9 \, x^{4} + 30 \, x^{3} + 37 \, x^{2} + 20 \, x + 4\right )} {\rm weierstrassPInverse}\left (\frac {19}{27}, -\frac {28}{729}, x + \frac {19}{18}\right ) + 10134 \, \sqrt {6} {\left (9 \, x^{4} + 30 \, x^{3} + 37 \, x^{2} + 20 \, x + 4\right )} {\rm weierstrassZeta}\left (\frac {19}{27}, -\frac {28}{729}, {\rm weierstrassPInverse}\left (\frac {19}{27}, -\frac {28}{729}, x + \frac {19}{18}\right )\right ) + 27 \, {\left (3378 \, x^{3} + 8410 \, x^{2} + 6839 \, x + 1813\right )} \sqrt {3 \, x^{2} + 5 \, x + 2} \sqrt {2 \, x + 3}\right )}}{81 \, {\left (9 \, x^{4} + 30 \, x^{3} + 37 \, x^{2} + 20 \, x + 4\right )}} \]

input
integrate((5-x)*(3+2*x)^(3/2)/(3*x^2+5*x+2)^(5/2),x, algorithm="fricas")
 
output
2/81*(2147*sqrt(6)*(9*x^4 + 30*x^3 + 37*x^2 + 20*x + 4)*weierstrassPInvers 
e(19/27, -28/729, x + 19/18) + 10134*sqrt(6)*(9*x^4 + 30*x^3 + 37*x^2 + 20 
*x + 4)*weierstrassZeta(19/27, -28/729, weierstrassPInverse(19/27, -28/729 
, x + 19/18)) + 27*(3378*x^3 + 8410*x^2 + 6839*x + 1813)*sqrt(3*x^2 + 5*x 
+ 2)*sqrt(2*x + 3))/(9*x^4 + 30*x^3 + 37*x^2 + 20*x + 4)
 
3.27.24.6 Sympy [F]

\[ \int \frac {(5-x) (3+2 x)^{3/2}}{\left (2+5 x+3 x^2\right )^{5/2}} \, dx=- \int \left (- \frac {15 \sqrt {2 x + 3}}{9 x^{4} \sqrt {3 x^{2} + 5 x + 2} + 30 x^{3} \sqrt {3 x^{2} + 5 x + 2} + 37 x^{2} \sqrt {3 x^{2} + 5 x + 2} + 20 x \sqrt {3 x^{2} + 5 x + 2} + 4 \sqrt {3 x^{2} + 5 x + 2}}\right )\, dx - \int \left (- \frac {7 x \sqrt {2 x + 3}}{9 x^{4} \sqrt {3 x^{2} + 5 x + 2} + 30 x^{3} \sqrt {3 x^{2} + 5 x + 2} + 37 x^{2} \sqrt {3 x^{2} + 5 x + 2} + 20 x \sqrt {3 x^{2} + 5 x + 2} + 4 \sqrt {3 x^{2} + 5 x + 2}}\right )\, dx - \int \frac {2 x^{2} \sqrt {2 x + 3}}{9 x^{4} \sqrt {3 x^{2} + 5 x + 2} + 30 x^{3} \sqrt {3 x^{2} + 5 x + 2} + 37 x^{2} \sqrt {3 x^{2} + 5 x + 2} + 20 x \sqrt {3 x^{2} + 5 x + 2} + 4 \sqrt {3 x^{2} + 5 x + 2}}\, dx \]

input
integrate((5-x)*(3+2*x)**(3/2)/(3*x**2+5*x+2)**(5/2),x)
 
output
-Integral(-15*sqrt(2*x + 3)/(9*x**4*sqrt(3*x**2 + 5*x + 2) + 30*x**3*sqrt( 
3*x**2 + 5*x + 2) + 37*x**2*sqrt(3*x**2 + 5*x + 2) + 20*x*sqrt(3*x**2 + 5* 
x + 2) + 4*sqrt(3*x**2 + 5*x + 2)), x) - Integral(-7*x*sqrt(2*x + 3)/(9*x* 
*4*sqrt(3*x**2 + 5*x + 2) + 30*x**3*sqrt(3*x**2 + 5*x + 2) + 37*x**2*sqrt( 
3*x**2 + 5*x + 2) + 20*x*sqrt(3*x**2 + 5*x + 2) + 4*sqrt(3*x**2 + 5*x + 2) 
), x) - Integral(2*x**2*sqrt(2*x + 3)/(9*x**4*sqrt(3*x**2 + 5*x + 2) + 30* 
x**3*sqrt(3*x**2 + 5*x + 2) + 37*x**2*sqrt(3*x**2 + 5*x + 2) + 20*x*sqrt(3 
*x**2 + 5*x + 2) + 4*sqrt(3*x**2 + 5*x + 2)), x)
 
3.27.24.7 Maxima [F]

\[ \int \frac {(5-x) (3+2 x)^{3/2}}{\left (2+5 x+3 x^2\right )^{5/2}} \, dx=\int { -\frac {{\left (2 \, x + 3\right )}^{\frac {3}{2}} {\left (x - 5\right )}}{{\left (3 \, x^{2} + 5 \, x + 2\right )}^{\frac {5}{2}}} \,d x } \]

input
integrate((5-x)*(3+2*x)^(3/2)/(3*x^2+5*x+2)^(5/2),x, algorithm="maxima")
 
output
-integrate((2*x + 3)^(3/2)*(x - 5)/(3*x^2 + 5*x + 2)^(5/2), x)
 
3.27.24.8 Giac [F]

\[ \int \frac {(5-x) (3+2 x)^{3/2}}{\left (2+5 x+3 x^2\right )^{5/2}} \, dx=\int { -\frac {{\left (2 \, x + 3\right )}^{\frac {3}{2}} {\left (x - 5\right )}}{{\left (3 \, x^{2} + 5 \, x + 2\right )}^{\frac {5}{2}}} \,d x } \]

input
integrate((5-x)*(3+2*x)^(3/2)/(3*x^2+5*x+2)^(5/2),x, algorithm="giac")
 
output
integrate(-(2*x + 3)^(3/2)*(x - 5)/(3*x^2 + 5*x + 2)^(5/2), x)
 
3.27.24.9 Mupad [F(-1)]

Timed out. \[ \int \frac {(5-x) (3+2 x)^{3/2}}{\left (2+5 x+3 x^2\right )^{5/2}} \, dx=-\int \frac {{\left (2\,x+3\right )}^{3/2}\,\left (x-5\right )}{{\left (3\,x^2+5\,x+2\right )}^{5/2}} \,d x \]

input
int(-((2*x + 3)^(3/2)*(x - 5))/(5*x + 3*x^2 + 2)^(5/2),x)
 
output
-int(((2*x + 3)^(3/2)*(x - 5))/(5*x + 3*x^2 + 2)^(5/2), x)